Core answer: Trapezoid area = (a + b)/2 × h — the average of the two parallel sides times the height. A roof face with 8 m eaves, 4 m ridge, and 3 m height covers (8+4)/2 × 3 = 18 m². The formula hides a trick: it's exactly the area of a rectangle with the *average* width.

Why averaging works

Slice a trapezoid with a diagonal or rotate a copy 180° to make a parallelogram: two trapezoids form a parallelogram of base (a+b) and height h, so one trapezoid is (a+b)h/2. The "midsegment" — the segment joining the legs' midpoints — has length exactly (a+b)/2 and splits the trapezoid into two equal-height halves.

Where trapezoids appear

Scenea / b / hArea
Roof gable face8 m / 4 m / 3 m18 m²
Garden bed (tapered)6 m / 4 m / 10 m50 m²
Road cross-section12 m / 8 m / 0.5 m5 m²
Swimming pool profile10 m / 6 m / 2 m deep16 m² → × width = volume

Worked examples

Example 1 — Pool volume. A 25 m pool, depth sloping 1.2 m to 2 m, width 10 m: profile is a trapezoid with parallel sides 1.2 and 2 m, "height" 25 m. Profile area = (1.2+2)/2 × 25 = 40 m²; volume = 40 × 10 = 400 m³ = 400,000 L. Water bill at ¥4/m³: ¥1,600 per fill.

Example 2 — Tapered flower bed. Ends 3 m and 1.5 m wide, 8 m long: (3+1.5)/2 × 8 = 18 m²; mulch at 5 cm depth needs 0.9 m³.

Example 3 — Land parcel. A plot between parallel roads: frontages 20 m and 35 m, depth 40 m → (20+35)/2 × 40 = 1,100 m² ≈ 1.65 mu.

Common mistakes and myths

  1. Using a slanted leg as height — height is the perpendicular distance between the parallel sides; an isosceles trapezoid's leg must be corrected via Pythagoras.
  2. Averaging the legs — only the two PARALLEL sides average; the legs (non-parallel) don't enter the formula.
  3. Forgetting perimeter needs all four sides — area ignores leg angles; fencing needs each leg measured or computed.
  4. Assuming any quadrilateral averages opposite sides — that only works when one pair is parallel; general quadrilaterals need diagonal-splitting.
  5. Unit slips on mixed units — 8 m eaves vs 300 cm height: convert before averaging.